AOJ Volume0 no.010
三角形の外接円の半径と中心座標を出す問題
提出した結果はRunTimeErrorで、main文が「0」を返さないといけないらしいが
return 0;
にしてもダメだった。解決方法わからず。。。
package levelZero; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; class CircumscribedCircleofATriangle { /**package levelZero; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; class CircumscribedCircleofATriangle { /** * @param args * @throws IOException */ public static void main(String[] args) throws IOException { InputStreamReader isr = new InputStreamReader(System.in); BufferedReader br = new BufferedReader(isr); String buf = br.readLine(); int dataSetNum = Integer.parseInt(buf); for (int i = 0; dataSetNum > i; i++) { String buf2 = br.readLine(); String[] point = buf2.split(" "); double x1 = Double.parseDouble(point[0]); double y1 = Double.parseDouble(point[1]); double x2 = Double.parseDouble(point[2]); double y2 = Double.parseDouble(point[3]); double x3 = Double.parseDouble(point[4]); double y3 = Double.parseDouble(point[5]); double ax = (x1 - x2); double ay = (y1 - y2); double a = Math.sqrt(ax * ax + ay * ay); double bx = (x2 - x3); double by = (y2 - y3); double b = Math.sqrt(bx * bx + by * by); double cx = (x3 - x1); double cy = (y3 - y1); double c = Math.sqrt(cx * cx + cy * cy); double radius = (a * b * c) / (Math.sqrt((a + b + c) * (-a + b + c) * (a - b + c) * (a + b - c))); double a1 = 2 * (x2 - x1); double b1 = 2 * (y2 - y1); double c1 = (x1 * x1 - x2 * x2 + y1 * y1 - y2 * y2); double a2 = 2 * (x3 - x1); double b2 = 2 * (y3 - y1); double c2 = (x1 * x1 - x3 * x3 + y1 * y1 - y3 * y3); double centerX = (b1 * c2 - b2 * c1) / (a1 * b2 - a2 * b1); double centerY = (c1 * a2 - c2 * a1) / (a1 * b2 - a2 * b1); System.out.print(centerX + " "); System.out.print(centerY + " "); System.out.print(radius + " "); } br.close(); } }