AOJ Volume0 no.010

三角形の外接円の半径と中心座標を出す問題

提出した結果はRunTimeErrorで、main文が「0」を返さないといけないらしいが
return 0;
にしてもダメだった。解決方法わからず。。。

package levelZero;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

class CircumscribedCircleofATriangle {

	/**package levelZero;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

class CircumscribedCircleofATriangle {

	/**
	 * @param args
	 * @throws IOException
	 */
	public static void main(String[] args) throws IOException {
		InputStreamReader isr = new InputStreamReader(System.in);
		BufferedReader br = new BufferedReader(isr);
		String buf = br.readLine();
		int dataSetNum = Integer.parseInt(buf);

		for (int i = 0; dataSetNum > i; i++) {
			String buf2 = br.readLine();

			String[] point = buf2.split(" ");

			double x1 = Double.parseDouble(point[0]);
			double y1 = Double.parseDouble(point[1]);

			double x2 = Double.parseDouble(point[2]);
			double y2 = Double.parseDouble(point[3]);

			double x3 = Double.parseDouble(point[4]);
			double y3 = Double.parseDouble(point[5]);

			double ax = (x1 - x2);
			double ay = (y1 - y2);
			double a = Math.sqrt(ax * ax + ay * ay);

			double bx = (x2 - x3);
			double by = (y2 - y3);
			double b = Math.sqrt(bx * bx + by * by);

			double cx = (x3 - x1);
			double cy = (y3 - y1);
			double c = Math.sqrt(cx * cx + cy * cy);

			double radius = (a * b * c)
					/ (Math.sqrt((a + b + c) * (-a + b + c) * (a - b + c)
							* (a + b - c)));

			double a1 = 2 * (x2 - x1);
			double b1 = 2 * (y2 - y1);
			double c1 = (x1 * x1 - x2 * x2 + y1 * y1 - y2 * y2);
			double a2 = 2 * (x3 - x1);
			double b2 = 2 * (y3 - y1);
			double c2 = (x1 * x1 - x3 * x3 + y1 * y1 - y3 * y3);

			double centerX = (b1 * c2 - b2 * c1) / (a1 * b2 - a2 * b1);
			double centerY = (c1 * a2 - c2 * a1) / (a1 * b2 - a2 * b1);

			System.out.print(centerX + " ");
			System.out.print(centerY + " ");
			System.out.print(radius + " ");
		}
		br.close();
	}
}